1) from point Pon the parabola x^2=2y a tangent is dran. From focus (S), a perpendicular is drawn to meet the tangent at R
a) find the equation of SR
b) find the locus of R
2) Show that the locus of the mid-ponts of chords in the parabola x^2= 4ay which passes through the vertex is the parabola x^2=2ay
(for qn. 2 I can do it if instead of the locus passing through the vertex, you ony consider focal chords but for this one I'm stuck)
2007-08-09 12:42:48 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2) the cords are y = mx as vertix is (0,0)
Intercept x^2-4amx= 0
midpoint x=2am and y = 2am^2 so m= x/2a and
y= 2ax^2/4a^2 = x^2/2a,so x^2=2ay
2007-08-11 07:59:01 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
rearrange the equations to y= y= 2x - 4 y= (x^2)/4 then make those corresponding to a minimum of one yet yet another 2x - 4=(x^2)/4 then rearrange so this equation =0 0.25x^2 - 2x + 4 =0 then using quadratic formulation materials x=4
2016-10-09 21:31:00 · answer #2 · answered by ? 4 · 0⤊ 0⤋
I think they have a spray to get rid of locus.
2007-08-09 12:47:22 · answer #3 · answered by Anonymous · 2⤊ 0⤋