Find the length and width if the perimeter of the rectangle is 60 units? Translate to an algebraic equation.
2007-08-09 11:54:28 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
2w + 2L = 60
L = w + 6
so substitute...
2w + 2(w+6) = 60 --> 2w + 2w + 12 = 60
4w = 48
w = 12, L = 18
2007-08-09 12:03:34 · answer #1 · answered by Ellee C. 2 · 0⤊ 0⤋
You need the length and width (L & W).
If L is six longer than W, than L=W+6.
Perimeter (P) is 2L + 2W. .
P=60, so 60=2(L) + 2(W). L=W+6, so plug that in for L on the perimeter equation.
60=2(W+6) + 2W... multiply it out, so 2W+12+2W =60
Combine like terms and you get 4W+12=60
Subtract 12 from both sides and you get
4W=48
Divide by 4
W=12....
If L=W+6, and W=12, then 12+6=18
L=18 and W=12
2007-08-09 19:09:56 · answer #2 · answered by Nardoff 2 · 0⤊ 0⤋
Let L=Length, and W=Width. P=Perimeter.
Equation
P=2(L+W)
Known values
P=60, L=W+6
Substitution
60=2(W+6+W)
Combine like terms
60=2(2W+6)
Multiply all terms within brackets by 2
60=4W+12
Subtract 12 from both sides
48=4W
Divide by 4 on both sides
12=W
Thus, the width is 12 units, and the length is six more, 18 units.
2007-08-09 19:05:34 · answer #3 · answered by lahooozuhher 1 · 0⤊ 0⤋
length =l=width + 6 units
width = w
perimeter is 2L+2W=60 units
2(w+6)+2w=60
2w+12+2w=60
4w+12=60
4w=48
w=12
l = 12+6 =18
12+12+18+18=60
24+36=60
60=60
2007-08-09 19:03:47 · answer #4 · answered by navy_bison 3 · 0⤊ 0⤋
so, width = x, length = x + 6
perimeter = 2x + (2(x+6))
60 =4x+12
48 = 4x
x =12
Length = 18, width 12
2007-08-09 19:00:05 · answer #5 · answered by open4one 7 · 0⤊ 0⤋
x = one side
x + 6 = the longer side
So
2(x + x + 6) = 60
Reduced:
2(2x+6)=60
...I think. It's been a few years since I needed that info.
2007-08-09 19:01:17 · answer #6 · answered by Anonymous · 0⤊ 0⤋
lenght is 25 and width is 35 so...
2007-08-09 18:59:01 · answer #7 · answered by ♥ Hello 3 · 0⤊ 1⤋