Please help with A2 Maths Question - Algebraic Fractions?

Question

2(x+3)^2 / x^2(x-1) divide by 10(x^2 - 9) / 2x^2 + x + 3

I have simplified, flipped the fraction on the right over and multiplied them but still can't get the right answer. I get
(x+3)(2x+3) / 5x^2 (x-3) evertime but the answer says
(x+3)(2x+3) / 5x^3 (x-3) (the 5x being cubed not squared).

If anyone call help by telling me if I have proved the answer wrong or have gone wrong myseld then thanks, it would also be helpful to know where I have gone wrong. I've gone over this loads and it's really annoying!

jfofnian - I'm sorry - it is indeed 2x^2 +x -3.
Does this mean I am correct?

Answer 1

[2(x + 3)²/x²(x - 1)][(2x + 3)(x - 1)]/[10(x - 3)(x + 3)]
[ 2 (x + 3) (2x + 3) ] / 10 x ² (x - 3)
[ (x + 3) (2x + 3) ] / [ 5 x ² (x - 3) ]

Answer 2

2(x+3)^2 / x^2(x-1) divide by 10(x^2 - 9) / (2x^2 + x + 3)
= 2(x+3)^2 / x^2(x-1) * (2x^2 + x + 3) / 10(x^2 - 9)
= 2(x+3)^2 / x^2(x-1) * (2x^2 + x + 3) / 10(x+3)(x-3)
= 2(x+3)^2(2x^2 + x + 3) / 10x^2(x-1)(x+3)(x-3)
= (x+3)(2x^2 + x + 3) / 5x^2(x-1)(x-3)

However, if it is a typo and the "+" should actually be a "-",
then:
(x+3)(2x^2 + x - 3) / 5x^2(x-1)(x-3)
= (x+3)(2x+3)(x-1) / 5x^2(x-1)(x-3)
= (x+3)(2x+3) / 5x^2(x-3)

Answer 3

♠ = {2(x+3)^2 /(x^2(x-1))}/{10(x^2 - 9) /(2x^2 + x ▬ 3)} =
= {2(x+3)^2 *(2x+3)(x-1)} /{x^2(x-1) *10(x^2-9)} =
= (x+3)(2x+3) / {5x^2 (x-3)};

and stop playing under the desk; there's a typo!

Answer 4

As you've typed it, your question doesn't actually give either of those answers!

If you meant 2x^2 + x - 3, as opposed to 2x^2 + x + 3, then the answer does indeed come out as the answer you think it should be, and the given answer must be wrong.

If that's not the typo you made, you'll need to edit the question before I can help further!

Edit:
Yes, Will, you are correct!

Answer 5

Clue
10(x^2-9)

will form part of the divisor
this can be factorized thus 10(x+3)(x-3) diff of 2 squares

in the numerator you have2(x+3)^2

take it from there!

Answer 6

specific. first of all, verify all the denominators are thoroughly factored. you may element a adverse sign out of the 0.33 one, and then element it utilising the version of two squares: a^2 - b^2 = (a+b)(a-b) 3/(a-x) + a million/(a+x) - (4x)/-(a^2 - x^2) 3/(a-x) + a million/(a+x) + (4x)/((a+x)(a-x)) Now locate the least uncomplicated denominator. liquid crystal show = (a-x)(a+x) Multiply the numerator and denominator of each term via the lacking element(s). (3*(a+x)) / ((a-x)*(a+x)) + (a million*(a-x)) / ((a+x)*(a-x)) + (4x) / ((a-x)(a+x)) Now that all of them have uncomplicated denominators, you may upload the numerators. (3(a+x) + (a-x) + 4x) / ((a-x)(a+x)) Distribute the three interior the numerator and drop the parenthesis around (a-x). (3a + 3x + a - x + 4x) / ((a-x)(a+x)) combine like words. (4a + 6x) / ((a-x)(a+x)) you're truly accomplished right here with the aid of fact it would not simplify, yet once you like to, you may multiply the denominator lower back out. (4a + 6x) / (a^2 - x^2)

Answer 7

{2(x+3)^2/x^2(x-1)}/{10(x^2-9)/2x^2+x-3}
= {2(x+3)^2.(2x^2+x-3)/{x^2(x-1).10(x^2-9)}
={2(x+3)^2(x-1)(2x+3)}/{10x^2(x-1)(x-3)(x+3)}
=(x+3)(2x+3)/5x^2(x-3) ans