2007-08-09 06:46:17 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x (x² - 9) = 2x (x - 3) (x + 3)
2007-08-09 08:54:46 · answer #1 · answered by Como 7 · 3⤊ 0⤋
put 2x in factor
2x^3-18x = 2x(x^2-9) = 2x(x-3)(x+3)
2007-08-09 13:50:51 · answer #2 · answered by maussy 7 · 0⤊ 0⤋
2x^3 - 18x
==> pull out CGF
2x (x^2 - 9)
==> difference of squares: (a^2 - b^2) = (a + b)(a - b)
2x (x + 3) (x - 3)
Your answer is 2x(x + 3)(x - 3).
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2007-08-09 13:49:36 · answer #3 · answered by C-Wryte 4 · 0⤊ 1⤋
2x^3-18x=2x(x^2-9)
2007-08-09 13:51:28 · answer #4 · answered by Anonymous · 0⤊ 0⤋
2x(x^2 - 9)
2x(x+3)(x-3)
2007-08-09 13:49:52 · answer #5 · answered by tkquestion 7 · 2⤊ 0⤋
2x^3-18x
=2x(x^2-9)
=2x{(x)^2-(3)^2}
=2(x+3)(x-3)
2007-08-09 13:49:40 · answer #6 · answered by alpha 7 · 3⤊ 0⤋