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okay so i have asked a question similar to this.. but im going to make it a little harder this time..
what you do is you have to use the numbers 0-9, one time each and make them equal 100.
but you can only use either all addition,subtraction, multiplication, or all division. exp (?+?+?+?=100)
or you can use them all one time each. exp. (?+?*?-?/?=100)

good luck! =]

2007-08-09 05:18:53 · 7 answers · asked by miss lyss 2 in Science & Mathematics Mathematics

did you guys not read all of it.
you cant use 2 different signs, unless you use all of them.

2007-08-09 05:34:08 · update #1

7 answers

9*8+7+6+5+4+3+2+1= 100

2007-08-09 05:26:42 · answer #1 · answered by Anonymous · 0 3

9*8+7+6+5+4+3+2+1= 100

2007-08-09 06:11:07 · answer #2 · answered by Anonymous · 0 1

8+4+1-6+2*9/3-7*5 = 100

2007-08-09 05:33:43 · answer #3 · answered by Anonymous · 0 1

9*8+7+6+5+4+3+2+1+0=100
it wasn't all that hard

2007-08-09 05:28:21 · answer #4 · answered by Anthony W 2 · 0 1

98+2*1-0/34567 = 100

Sin©e you need to apply hierarchy of operations, this is ...
98+(2*1)-(0/34567)
= 98 + 2 - 0
= 100.

You can also change the 8 & 2 by any of the other numbers that will add up to 10, except 9,1&0.
Thus: 97 + 3*1 - 0/ 24568 = 100

PS. thanks kyle for leading me to this. :)

Note:
It is previously discussed that the pure addition operation is impossible.
It is also clear that the pure multiplication leads to 0 or another multiple of 10 but not 100=2*2*5*5.
Subtraction and division will lead to ambiguous expressions.

2007-08-10 07:38:21 · answer #5 · answered by Alam Ko Iyan 7 · 3 0

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2016-11-11 20:43:32 · answer #6 · answered by bhupender 4 · 0 0

any thing honey

9*5*2=90+8+7+4-3-6=100

2007-08-09 05:37:42 · answer #7 · answered by Anonymous · 0 1

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