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Theory of relativily clearly states that energy can never be lost, only trasferred. So what does this say about the energy that each photon carries?

2007-08-09 04:26:43 · 7 answers · asked by ionbreather 2 in Science & Mathematics Astronomy & Space

7 answers

Maybe it goes into a wormhole until enough energy collects to birth a new star elsewhere in the universe.

2007-08-09 04:30:51 · answer #1 · answered by cop350zx 5 · 0 2

for sure one can not "see" a black hollow, yet you may see what's happening on its adventure horizon. This marks the radius interior which mild can now no longer escape, although that is not any longer the black hollow itself. we would be waiting to visual reveal unit the exterior for clues yet interior we are able to purely theorize. we are able to make particular that count and potential do no longer behave many times there. Gravity would be so extreme that different forces, electromagnetism, the reliable and susceptible atomic forces, would be crushed. Atoms would probably be broken down into individual quarks, flowing and colliding, held at the same time by using sheer proximity with the aid of rigidity of gravity. Photons ought to preserve their "velocity" yet would no longer likely be traveling in a straight away line. it would be extra like a vibration than a vector. that is meaningless to describe what an observer interior the black hollow observes with the aid of fact an observer is impossible. count purely would not behave in a manner shall we "be conscious". with the aid of fact the mass of a black hollow will improve, the form horizon ought to enhance yet we don't have a sparkling theory of the barriers of issues. some issues DO escape from black holes, "geysering" from the poles. the way all of it balances out will take lots extra learn.

2016-10-09 16:10:07 · answer #2 · answered by ? 4 · 0 0

No, it isn't expelled through the poles in the form of X-rays.

No, it doesn't go through a wormhole.

And no, it's not true that light can't enter a black hole.

What happens is, the energy from the photon manifests itself as increased mass of the black hole. (Remember that mass and energy are basically the same thing.)

2007-08-09 04:40:33 · answer #3 · answered by RickB 7 · 3 0

The energy is brought to the center of mass withing the black hole. A black hole is really a star that has collapsed into itself. It isnt like a void of matter destruction. All the energy and mass, just remains there.

2007-08-09 04:30:57 · answer #4 · answered by billgoats79 5 · 2 0

The photon loses no energy it merely circles the event horizon for all time.

2007-08-12 05:41:55 · answer #5 · answered by johnandeileen2000 7 · 0 0

The energy is expelled through the poles in the form of X rays

2007-08-09 04:30:29 · answer #6 · answered by most important person you know 3 · 0 2

even light cannot pass/enter the black hole.

2007-08-09 04:31:04 · answer #7 · answered by Ishu 1 · 0 2

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