Find the angular velocity of a ferris wheel with a diameter of 208ft that takes 25secs to rotate once. Please express the answer in terms of pie. Thanks :)
2007-08-08 22:03:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Angular velocity = Anguilar displacement/time
= circumference of ferrari wheel/time
= (pi*d)/25
= pi*8.32 ft/sec
= 8.32*pi ft/sec.
Substitute the value of pi and get the actual value of angular velocity.
2007-08-08 22:16:43 · answer #1 · answered by Beurself 2 · 0⤊ 1⤋
You have to be careful with circular motion here.
There are 2 types of velocity involved. Angular and linear.
Angular velocity is angle divided by time. In your case the Ferris wheel completes 2pi radians or 360 deg in 25 sec so:
Angular velocity = 2pi/25 = pi/12.5 radians per sec also
Angular velocity = 360/25 = 14.4 degrees per sec
Now for a person sitting in one of the gondolas at the edge of the wheel the circular motion speed will feel like a linear linear motion of :
208 * pi / 25 = 8.32*pi/sec this is the tangential speed which can be understood as the linear equivalent of the circular speed.
2007-08-11 15:18:48 · answer #2 · answered by 037 G 6 · 0⤊ 0⤋
It has nothing to do with the diameter.
Ï = 2Ï/T
= 2Ï/25 = 0.2513 rad/sec
2007-08-11 15:16:16 · answer #3 · answered by Dr D 7 · 0⤊ 0⤋