What AMOUNT of NaCl is generated by the reaction of 50g of Na2Co3 with HCL? Na2CO3 + HCL = NaCl + CO2 +H2O?

0 ⤊

What AMOUNT of NaCl is generated by the reaction of 50g of Na2Co3 with HCL? Na2CO3 + HCL = NaCl + CO2 +H2O?

2007-08-08 21:39:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

3 answers

1 mole Na2CO3 gives 2mole NaCl after balancing the equation
Na2CO3 + 2HCL = 2NaCl + CO2 +H2O?
106g -------------------------------> 58*2g NaCl approx
50g-------------------------------> 58*50*2/106
i.e 54.7g approx

2007-08-08 21:50:04 · answer #1 · answered by brindha 2 · 0⤊ 0⤋

The correct equation is Na2CO3 + 2HCl ----> 2NaCl + CO2 + H2O

The mass of NaCl is (50/106) x 2 x 58.5 grams.

2007-08-08 21:45:36 · answer #2 · answered by Gervald F 7 · 0⤊ 1⤋

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
Amount of NaCl form = 50 X (58.45 / 106 ) ( 2) = 55.14 g

2007-08-09 01:50:30 · answer #3 · answered by Yheng Natividad 3 · 0⤊ 1⤋