Jack did a study in which he looked at average frequency and length of words in a sentence. The average word frequency in his study was 11257 and sample size 50. another student disagreed and thought that the average word frequency was higher than the average word frequency a normal sentence should have. Jack find the average word frequency for a normal sentence 10666 occurrences per million and SD= 5000. jack finds his finding close to frequency and ignores the other student. Test hypothese using 2-tailed test and p less than .05. is jack right?
How do we do this ?
2007-08-08 19:17:06 · 1 answers · asked by aaachooooo 1 in Science & Mathematics ➔ Mathematics
Ho: µ1 = 10666
Ha: µ1 not equal 10666 (two-tailed)
α = 0.04
Zcritical =± Z(sub α/2) = ±1.96
ZCalculated = (11257 - 10666)/(5000/√50) = 0.836
Conclusion: Because 0.836 is not in the critical region, we cannot reject Ho and conclude that Jack is correct.
2007-08-09 01:33:06 · answer #1 · answered by cvandy2 6 · 0⤊ 0⤋