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i have a test tomorrow, and i just wanted to understand these problems more.
so if you can work them out for me.
thanx !!!

1. solve (x-2)SQUARED=25

2. solve 5xSQUARED + 30x = 0

3. what are the x-intercepts of the equation 5xSQUARED - 20 = 0


the SQUARED thingies are like.
the the second power.

2007-08-08 19:07:43 · 8 answers · asked by classy.chic 3 in Education & Reference Homework Help

8 answers

I wrote it out in paint. If you dont understand anything e-mail me. good luck in your exam.

http://img125.imageshack.us/img125/8305/untitledht7ey4.jpg

2007-08-08 19:33:27 · answer #1 · answered by Anonymous · 1 0

I aint dat sure was thru wit skul sm tym back

1. open up = (x-2) * (x-2) = 25
x squared - 2x -2x +4 = 25
x squared -4x +4 =25
x squared -4x +4 -4 =25-4
x squared - 4x = 21
factor out x
x(x-4) =21

...........im stuck ......get someone to help you from there im sure im on the right track just that i dont remember if you get the log on both sides or something else....... :-)

2. in the second question take 30x to the other side
5xsquared = -30x
divide both sides by x
5x squared/x = -30x/x
5x= -30
divide both sides by 5
5x/5 = -30/5
x = - 6 (negative 6)

3. 5x squared -20 = 0
take 20 on the other side
5x squared - 20 +20 = 0 +20
5x squared = 20
divide both sides by 5
5 x squared / 5 = 20/5
x squared = 4
get square root
x = 2 the other intercept is x= - 2
(negative x negative = positive) (-2 x -2 = +4)


Have fun with the math

2007-08-09 02:39:30 · answer #2 · answered by baby gal 3 · 0 0

(x-2)^2 is the same as (x-2)(x-2), right?
so (x-2)(x-2) = 25
now, you need to work further:
(x-2)(x-2) = 25
x^2 - 4x + 4 = 25
x^2 - 4x = 25 - 4
x(x - 4) = 21
x = 7

2) 5x^2 + 30x = 0 5x(x + 6) = 0 (x + 6) = 0 and 5(-6)(0) will be 0

i'm sorry, but i can't help you with nr. 3, i don't really understand all of the english terminology (i have it in afrikaans)

2007-08-08 19:30:53 · answer #3 · answered by Flakkenmarsh 3 · 1 0

1. taking squareroot on both sides

(x-2)squarroot = (25)squareroot

(x-2) = 5
x-2 = 5
adding 2 0n both sides
x-2+2 = 5+2
x+0 = 7
x = 7 solved
2. taking x common from equation
x(5square x + 30) = 0
5square x +30 =0
25x + 30 = 0
25x = -30
x = 30/25 dividing both sides by 25
so x = 6/5 solved

2007-08-08 19:28:02 · answer #4 · answered by kashifsani87 1 · 1 1

1.) (x - 2)squared = 25
x - 2 = squareroot of 25
x = 5

2.) 5x squared + 30x = 0
5x squared = -30x
5x squared divided by x = -30
5x = -30
x = -30 divided by 5
x = -6

2007-08-08 20:47:24 · answer #5 · answered by Anonymous · 0 0

Try yourself.
(x - 2) (x - 2) = 25
Simply you could say x = 7 but x = -3 too
remove the brackets you get
x^2 - 4x + 4 = 25 therefore
x^2 - 4x - 21 = 0 you go from here.

5x^2 + 30x = 0
5(x^2 + 6x) = 0
x can = +6 or -6

follow the same steps for three.

2007-08-08 19:17:16 · answer #6 · answered by jemhasb 7 · 0 3

hi buddy this an easy question in accordance with linear equations you ought to use transposition technique in this methodology while a term is transfered from one element to different its sign will become opposite answer: x+4-7x=22 =4-7x=22-x (right here x comes from the left element its sign differences) =4=22-x+7x(right here 7x comes from the left element its sign differences) =4-22=6x(same) =-18=6x x=-18/6 =-3 Bye Bye!!!!!!!!!!!!!!!!!!!!!!

2016-12-15 09:54:16 · answer #7 · answered by ? 4 · 0 0

Sorry but i have been out of high school for 10 yrs! Your already in school for the year dang school doesn't start in texas until like next week.

2007-08-08 19:25:07 · answer #8 · answered by Jason B 2 · 0 0

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