Two tuna boats leave the same port taveling in opposite directions along the west coast of the United States..

Question

Two tuna boats leave the same port traveling in opposite directions along the west coast of the United States. One boat travels 5 miles per hour faster than the other. At the end of one day of travel, they are 1080 miles apart. What is the speed of the faster boat?

A. 20
B. 25
C. 30
D. 35
E. 40

Answer 1

speed of the faster boat = v
speed of the slower boat = v - 5
Relative velocity = v + v-5 = 2v - 5

speed = distance/time
2v - 5 = 1080/24
2v - 5 = 45
2v = 50

v = 25 miles per hour

The speed of the faster boat is 25mph

B

Answer 2

Answer = B

Speed of boat 1 = x
Speed of boat 2 = x + 5

Total speed = x + x +5
Total time = 24 hours
Distance = 1080 miles

Therefore, (2*x +5)* 24 = 1080
or, 2x + 5 = 1080/24 = 45

2x + 5 = 45, x = (45-5)/2 = 20

slow boat = 20, faster boat = 25

Answer 3

If x is the speed of the slower boat in mi/hr, than 2x+5 is the miles apart in 1 hour. From the info, 2x+5= 1080/24 = 45, so x=20. THEN, the answer is B

Answer 4

y=total distance traveled in miles per hour
x=speed traveled by slower boat in miles per hour
y=x+(x+5)
y=2x+5

how many hours did they travel for?
it doesn't exactly say, but
lets say they traveled all day
1080 total miles/24 hours =45 miles per hour=y
plug into function y=2x+5
45=2x+5
40=2x
20=x

so if they traveled 24 hours straight, the slower boat went 20 miles per hour, and the faster boat went 25 miles per hour