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the answers are very specific and not imaginary numbers and they are based on a very simple math law

2007-08-08 15:44:58 · 11 answers · asked by billy t 1 in Science & Mathematics Mathematics

11 answers

0 and 1

2007-08-08 15:49:42 · answer #1 · answered by emm 4 · 0 0

x = 1 - y

2007-08-08 16:03:47 · answer #2 · answered by babygirl_isloved 3 · 0 0

Well. Did you realize what you are looking at is a formula for the circle of radius sqrt(1), which is 1?

As there are infinate number of x,y combinations, the only way to express ALL the possible numbers is either in formula or in graph.

I would answer like this: "X and Y coordinate pairs are expressed by a circule with a radius of 1"

You could also give examples but that won't be a complete answer.

You could also rewrite the formula in terms of Y or X. If you do, don't forget +/- sign.

The very simple math law you are supposed to be recognizing is the fact it is a circle with radius of 1.

2007-08-08 15:51:36 · answer #3 · answered by tkquestion 7 · 1 0

*=2 so X^2+Y^2=1, if X were to = 0 and Y were to =1 then 0^2+1^2=1 -> 0+1=1 -> 1=1, then vice versa.

2007-08-08 15:50:44 · answer #4 · answered by Tjj9000 3 · 0 0

x^2 + y^2 = r^2 is the definition of a Circle with center at x = 0,
y=0

So, this is a circle with radius = 1 ^ 0.5 = 1
Every point on the circle is a solution, so,
x=1, y=0 is a solution, I'll refer to this as (1,0) where 1 is the x and 0 the y.
(0,1) is a solution
(-1,0) is a solution
(0,-1) is a solution
These are the four points at 0 deg, 90 deg, 180 deg and 270 deg.

Similarly, (0.7071, 0.7071) at 45 deg is a solution
(0.7071,- 0.7071) at 135 deg is a solution
(-0.7071, 0.7071) at 225 deg is a solution, and
(-0.7071, -0.7071) at 315 deg is a solution

And just so you know, 0.7071 is the square root of 1/2

2007-08-08 15:57:12 · answer #5 · answered by Scott W 3 · 1 0

x^2 + y^2 = 1 graphs a circle with the center at the origin and it's radius of 1. Draw a sketch! There are an infinite number of answers, but four of them stick out to me when you see the graph!

2007-08-08 15:51:27 · answer #6 · answered by douglas 2 · 0 0

That is the equation of a unit circle, so all solutions are given by

x=cos(t)
y=sin(t)

for values of t between 0 and 2*pi, inclusive.

2007-08-08 15:53:35 · answer #7 · answered by ckoneak 1 · 1 0

x =1, y=0
x = 0, y = 1
x =1/2, y = Sqrt(3) /2
x = Sqrt(3) /2, y = 1/2

Any position on the unit circle (circle with radius 1), centered at (0,0)

2007-08-08 15:49:11 · answer #8 · answered by Jeƒƒ Lebowski 6 · 0 0

x^2 + y^2 =1
do you want y in terms of x? y = + or 1 sqrt (1-x^2) ??

2007-08-08 15:50:16 · answer #9 · answered by vlee1225 6 · 0 0

What the hell is an imaginary number? Are there a lot of fake numbers running amuck.

2007-08-08 15:49:57 · answer #10 · answered by Damn™ the Man 3 · 5 3

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