How do you solve 4x^2 -12x+3?

Question

please show how to solve it, not just the answers.
ive been argueing with someone about it all day and we keep coming up with different things.

Answer 1

4x^2-12x+3=0
comparing this with the standard quadratic equation ax^2+bx+c=0,we get
a=4,b= -12 and c=3
Therefore x
={12+-sqrt(144-48)/2*4
=(12+-sqrt96)/8
=(12+-4sqrt6)/8 ans

Answer 2

First. I have to assume that you mean 4x^2 -12x+3 = 0, because there is nothing to solve in your question.

There are two ways that both give you the same answer.

Completing the square is the first way.
4x^2 - 12x + 3 = 0
4(x^2 - 3x) + 3 = 0
4(x^2 - 3x) + 3 = 0
4(x^2 - 3x + 9 - 9) + 3 = 0
4(x^2 - 3x + 9/4 - 9/4) + 3 = 0
4(x^2 - 3x + 9/4) - 9 + 3 = 0
4(x - 3/2)^2 - 9 + 3 = 0
4(x - 3/2)^2 - 6 = 0
4(x - 3/2)^2 = 6
2(x - 3/2)^2 = 3
(x - 3/2)^2 = 3/2
x - 3/2 = +/-(3/2)^(1/2)
x = +/-(3/2)^(1/2) + 3/2
x = 3/2 +/- (3/2)^(1/2)

Quadratic Equation is the second way.
4x^2 - 12x + 3 = 0
x = (12 +/- (144 - 4(4)(3))^(1/2)) / (2)(4)
x = (12 +/- (144 - 48)^(1/2)) / 8
x = (12 +/- (96) ^ (1/2)) / 8
x = 12/8 +/- (96) ^ (1/2) / 8
x = 3/2 +/- (96) ^ (1/2) / 8
x = 3/2 +/- (96) ^ (1/2) / 64^(1/2)
x = 3/2 +/- (96 / 64)^(1/2)
x = 3/2 +/- (3/2)^(1/2)

Answer 3

Quadratic equation (-b +- √b²-4ac) / 2a

a=4 b=-12 c=3

-(-12)+- √-12²-4x4x3 / 2x4

=12+- √144 - 48 / 8

=(12+-√96) / 8
you could simplify it further by making two equations of
(12+√96)/8 and (12-√96)/8 using a calculator

Answer 4

Use the quadratic equation.
http://en.wikipedia.org/wiki/Quadratic_equation

Answer 5

it can't be solved