27-13(u-6)=54-(4u-24)
2007-08-08 07:02:33 · 7 answers · asked by dianajiminez 1 in Science & Mathematics ➔ Mathematics
27-13u+78=54-4u+24
105-13u=78-4u
9u=27
u=3.
2007-08-08 07:11:46 · answer #1 · answered by Alien 4 · 1⤊ 0⤋
= 27 - 13 (u - 6) = 54 - (4u - 24)
= 27 - 13u + 78 = 54 +24 - 4u
= 105 - 13u = 78 - 4u
= 105 - 78 = 13u - 4u
= 27 = 9u
= u = 3 -: ANS
2007-08-10 05:50:14 · answer #2 · answered by VIPUL 2 · 0⤊ 0⤋
First solve the brackets on both sides. bearing in mind – (minus) side outside the bracket.
27–13u + 78 = 54 – 4u + 24
105 –13u = 78 – 4u
9u = 27
u = 3.
2007-08-12 01:42:30 · answer #3 · answered by Pranil 7 · 0⤊ 0⤋
u=3
2007-08-08 07:06:36 · answer #4 · answered by csmithballsout 4 · 1⤊ 0⤋
27-13u+ 78=54-4u+24;
3+24=9u;
9u=27;
u=3;
2007-08-10 21:34:51 · answer #5 · answered by Anonymous · 0⤊ 0⤋
27-13u+ 78=54-4u+24;
3+24=9u;
9u=27;
u=3;
2007-08-08 20:25:53 · answer #6 · answered by Pallavi 2 · 1⤊ 0⤋
brackets
2007-08-08 22:34:16 · answer #7 · answered by baby elephant 3 · 0⤊ 0⤋