Need help I know the answer just need help showing work.....?

Question

P=1000√t+2000 ( t+2000 both are under the sqrt)
(P) is for population

Using this equation approximate how many years it would take for the population to reach 7000. Round the nearest whole year when necessary.


I think the answer is 25 years but I need to know the step by step how to.......

I am sry the only thing that is under the √
is (t)

Answer 1

P = 1000 sqrt(t) + 2000
If t is the time at which the population reaches 7000, then:
7000 = 1000 sqrt(t) + 2000
Subtracting 2000 from each side:
5000 = 1000 sqrt(t)
Dividing by 1000:
5 = sqrt(t)
Squaring:
t = 25.
The time is 25yr.

Answer 2

I think the correct equation is

P = 1000 x sqrt t + 2000 (2000 is not under the square root)

Thus for P = 7000

7000 = sqrt t x 1000 + 2000

sqrt t x 1000 = 5000

t = 25

If as you mentioned t + 2000 is inside the square root, even for t = 0, we have a P > 7000

Answer 3

P = 1000*sqrt(t+2000)

square everything:

P^2 = 1000^2*(t+2000)

P = 7000:

7000^2 = 1000^2*(t+2000)

49000000=1000000t+2000000000
49=t+2000
t = -1951 years

I am anticipating a mistake in your eqn...

Answer 4

Hmmm... I think there's a typo here, but I'll assume you typed it in correctly for now.

Use your formula substituting 7,000 for P
7000=1000*sqrt(t+2000)

Solve for t

7000/1000 = sqrt(t+2000)
7=sqrt(t+2000)
49=t+2000
t = -1951

That means your time is 1,951 years in the past. I think you have a number wrong in your formula, could you check your numbers again?

Answer 5

something's wrong: sqrt(2000) = 44.7, so even at time 0, P = almost 45000. please check problem or formulas