Math stumped.?

Question

Hi, I need help with negative fraction exponents, for example: x -1/3(-1/3 is an exponent) Yeah I don't know what to do there so I can't finish the whole part of this math problem. So can anyone tell me what to do with negative fraction exponents??? Thanks

So what if there was a number infront of the x? Thank you for your answers. =)

Answer 1

A negative exponent is one divided by the exponent. So x^-13 = 1/x^1/3.
Dividing an exponent by n is the equivalent of taking the nth root of a number, so x^-1/3 = 1/(3√)x or 1 divided by the third root of x. 8^-1/3, for example, = 1/2

Answer 2

x^(-1/3) here ^ stands for 'to the power' or exponent is 1 / x^(1/3). If you have a negative exponent , you can make it positive by putting it in the denominator. Treat the fraction as if it were an integer and proceed with your calculation.

Answer 3

x^( -1/3)
=1/x ^(1/3)

Answer 4

We can solve 3x^(-1/3) for an example.
First invert 3x so that you can ignore the negatve;(1/3x)^(1/3)
Then 1/3x^(1/3)or
One over the third rout of 3x

Answer 5

please use notation that makes it clear what you are trying to get us to see.

do you mean (x^(-1/3))^(-1/3)

rules of exponents

x^a times x^b = x^(a+b)
but
(x^a)^b = x^(ab)

so (x^(-1/3))(x^(-1/3)) would be x^(-2/3)
but
(x^(-1/3))^(-1/3) is x^(-1/9)

x^(-1/9) = 1/x^(1/9)

since I don't know the rest of the problem, I can't recommend anything beyond looking at the following link:
http://mathforum.org/library/drmath/sets/select/dm_neg_exponents.html

Answer 6

you can rewrite as:

1/(x^1/3)