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here my problem Im going into algebra 1 and I cant rember how you subract mixed number and Im having a difficult time remebering can someonone help?please and thank you for taking your time to read my problem.

2007-08-08 03:32:38 · 8 answers · asked by Unique 2 in Science & Mathematics Mathematics

I thought when you trun them into improper fractions you multiply the whole number times the denominator then you add the numerator stay with the same denominator but have a different numerator ,uhm am I correct?

2 3/6

2 times 6 = 12 plus 3 equals 15 and ou get 15/6 right?

2007-08-08 03:45:52 · update #1

Thougth what Im gaving problems with actually is subracting ,,dividing ,,multiplying,, fractions.

2007-08-08 04:00:12 · update #2

8 answers

Example 1
5 ¾ - 2 ½ = 3 ¼

Example 2
5 ¼ - 2 ½
4 5/4 - 2 2/4
2 ¾
OR
21 / 4 - 5 / 2
21 / 4 - 10 / 4
11 / 4
2 ¾
OR
3 (¼ - ½)
2 (5/4 - 2/4)
2 ¾

Hope you can find a method to suit from above.

2007-08-15 19:49:19 · answer #1 · answered by Como 7 · 0 0

Yes, you are correct - but John V makes a valid point regarding the matter of 'cancelling down' the two parts of the new fraction by any common factors.

For multiplication of two such newly created fractions, just multiply the two numerators to create one new one and do the same with the denominators. Then you can 'cancel down' again if possible, finally turning your answer into a mixed number.

To divide, simply use the rule 'invert the divisor & multiply'; i.e. turn the fraction by which you are dividing upside-down and then multiply by it instead.

Additions & subtractions are best handled by multiplying the two denominators together, then multilying the numerator of each fraction by the other's denominator & adding or subtracting (as appropriate) the results to give the numerator of the answer.

Whichever operation you perform, never forget to look for common factors in your answer to cancel down by.

I hope all this helps, but please feel free to drop me a line if you'd like me to say more. I have written a book on mental calculations, i.e. how to deal with numbers in your head, you might find some of the material useful - perhaps, one would hope, even interesting.

2007-08-08 05:39:06 · answer #2 · answered by general_ego 3 · 0 0

By mixed numbers I will assume you mean a number and a fraction, such as 2 3/4 .
You add these by converting them into one fraction without the whole number, finding a common denominator, adding, and reducing. Here's an example.

2 1/3 + 3 1/6 =?
Convert 2 1/3 to one fraction by multiplying by denom / denom
2 (3/3) = 6/3 + 1/3 = 7/3
3 (6/6) = 18/6 + 1/6 = 19/6

Find common denom, with 3 and 6, LCD = 6
Factor to multiply by = 6/3 = 2... so 2/2
7/3 * 2/2 = 14/6

Add... 14/6 + 19/6 = 33/6
Reduce... divide by 3 = 11/3
Finally split into mixed number again (if they ask you to)
11/3 = 9/3 + 2/3 = 3 2/3

Hope this helps!

2007-08-08 03:40:10 · answer #3 · answered by Jon G 4 · 0 0

Assumming a + (b/c) = a+b/c are mixed number.
You can always change this to become (a*c + b)/c
With this way, you can solve any mixed number.

Example :
2+3/4 ; you can transform to become
(2*4 + 3) / 4 =(8+3)/4 = 11/4

If you want to add/substract a mixed number, you have to convert the mixed number to becoming a fraction like the example above.

If the "Denominator" of the fraction/mixed number is different, you have to cross-multiply it.

example :
(2+3/4) + (3+4/5) =
= 11/4 + 19/5
= 5*11/5*4 + 4*19/4*5
= 55/20 + 76/20
= 131/20 = 6+11/20

Hope you'll understand this.
Don't hesitate to contact me via email
Cheerss :))))

2007-08-08 04:07:29 · answer #4 · answered by Mohamad Radhian M 3 · 0 0

E.g.
2 3/5 - 1 4/7
= (2-1) (3/5 - 4/7)
= 1 (21/35 - 20/35)
= 1 1/35

OR

2 3/5 - 1 4/7
= 13/5 - 11/7
= (13*7)/35 - (11*5)/35
= 36/35
= 1 1/35

2007-08-11 07:35:08 · answer #5 · answered by Kemmy 6 · 0 0

Correct.

2007-08-08 03:57:10 · answer #6 · answered by cidyah 7 · 0 0

most important step is to calculate the common denominator so that the fractions can be added or subtracted without difficulty.

2007-08-08 03:36:42 · answer #7 · answered by John V 6 · 0 0

Yeah, you're right. Maybe next time you can give more specifics so that I won't have difficulty in illustrating the mathematical principles related to your problem.

2007-08-12 03:46:07 · answer #8 · answered by Jun Agruda 7 · 2 0

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