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Write the equation of the line in the form Ax + By = C given the following.

1. Passing through the intersection of the lines x + 3y - 2 = 0 and 2x - y + 8= 0 and the points (-5,-1).

2. Passing through (-2,12) and has its x-intercept one half its y-intercept.

3. Passing through the vertec C(5, -3) of DABC and perpendicular to the side containing the other two vertices
A(-3,-4) and B(4,5).


THANKS AND GODBLESS

2007-08-08 03:22:36 · 2 answers · asked by xah8 1 in Science & Mathematics Mathematics

2 answers

x + 3y - 2 = 0
6x -3 y + 24= 0

add these equations

7x=-22
x=-22/7
y=2x+8
=56/7 - 44/7=12/7

write the line through these two points
(-5,-1).
(-22/7,12/7)

2007-08-08 04:05:56 · answer #1 · answered by iyiogrenci 6 · 0 0

y=5 is a horizontal line each and every time y= a persevering with it rather is a persevering with line(horizontal) vertical is whilst x= a persevering with diagonal line is a linear equation with slope secure (different than 0) y=mx+b is the linear equation

2016-12-11 13:57:06 · answer #2 · answered by Anonymous · 0 0

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