Find the area of a regular hexagon with side = 12 cm. Round your answer to the nearest tenth.?

Answer 1

Well, the area of an equilateral triangle of side x is (3^(1/2) * x^2) / 4. A regular hexagon is just 6 equilateral triangles, so the area of a regular hexagon is (3 * 3^(1/2) * x^2) / 2.

If x = 12, then (3 * 3^(1/2) * 144) / 2
A = 3 * 3^(1/2) * 72
A = 216 * 3(1/2)

To the nearest tenth,
A = 374.1 cm^2

Answer 2

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