2007-08-08 01:28:40 · 6 answers · asked by REYNALDO F 2 in Science & Mathematics ➔ Mathematics
step by step please.
2007-08-08 01:43:18 · update #1
x = [108 ± √(108² + 29040) ] / 2
x = [108 ± 202 ] / 2
x = 155 , x = - 47 (to nearest whole numbers)
2007-08-15 19:34:50 · answer #1 · answered by Como 7 · 0⤊ 0⤋
By using the quadratic formula,
x = (-b屉(b^2-4ac)) /2a
= (-(-108)±â((-ã108ã^2)-4(1)(-7260))/(2(1))
= (108± â40704)/2
= (108 + â40704)/2 or (108 - â40704)/2
= 154.876 or 46.876
2007-08-15 21:07:56 · answer #2 · answered by 痴心情长剑 3 · 0⤊ 0⤋
x^2 - 108x - 7,260 = 0
x^2 - 108x = 7,260
By approximation:
x = 154.876161703
Proof (substitute x with 154.876161703 in your original equation):
154.876161703^2 - 108(154.876161703) - 7,260 = 0
23,987(rounded) - 16,727(rounded) - 7,260 = 0
23,987 - 23,987 = 0
2007-08-15 15:01:35 · answer #3 · answered by Jun Agruda 7 · 2⤊ 0⤋
The quadratic formula:
x = [-b +/- sqrt(b^2 - 4ac)] / 2a
in your case, a is 1, b is -108 and c is -7260
after, doing the sums, you get
x=154.87616170334792 or x=-46.87616170334793
2007-08-08 01:39:00 · answer #4 · answered by Jeremy 2 · 0⤊ 0⤋
Just use the quadratic equation.
2007-08-08 01:31:10 · answer #5 · answered by Anonymous · 0⤊ 2⤋
x = 153.27903010881556
2007-08-08 01:45:38 · answer #6 · answered by Shane WhiteHorse 1 · 0⤊ 2⤋