2007-08-07 18:51:03 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Consider the trapezium with horizontal parallel sides of length a and b.
perpendicular height = h
Area of trapezium = (1/2)(a + b)(h) = A units²
Volume of this trapezium of base area, A and length H, would be given by:-
V = AH
V = (H/2)(a + b)(h) units³
2007-08-07 21:58:02 · answer #1 · answered by Como 7 · 1⤊ 0⤋
0 a trapezoid has no volume. Now if you meant area (A), then a trapezoid's area is calculated as
A= [(a+b)h]/2
where 'a' & 'b' are the parallel sides and 'h' is the distance between them.
If you do not know the value of 'h' then the sides being 'a','b','c' & 'd' where the parallel sides are 'a' and 'c' and 'a' is the longer side, the area 'A' is:
A=[(a+c)/4(-a-c)]â[(a+b-c+d) (a-b-c+d) (a+b-c-d) (-a+b+c+d)]
Now if you meant a trapezoidal prism, then just multiply the area (A) times the heigth (H) of the prism
V=AH
2007-08-07 18:56:29 · answer #2 · answered by ΛLΞX Q 5 · 0⤊ 1⤋
volume = area of trapezoid x h x L
. . . . = (a + b)/ 2 x h x L
where a and b are the two parallel sides
h is the distance between the parallel sides
L is the length of the through
2007-08-07 18:55:14 · answer #3 · answered by CPUcate 6 · 0⤊ 0⤋
A trapezoid is two triangles hooked onto a rectangle. Add the three areas (the two triangles + the rectangle) and multiply by the height, and, you have the volume:
V = [A(triangle 1) + A(triangle 2) + A(rectangle)]h
2007-08-07 18:56:15 · answer #4 · answered by kellenraid 6 · 0⤊ 0⤋
A = 1/2(bh) or A = (bh)/2
2007-08-07 18:56:01 · answer #5 · answered by Bob Loblaw 2 · 0⤊ 0⤋