Alright. I've been trying to figure this out for years. I'm hoping to gain some insight into this unique number.
Let me set it up.
Take a number, any number (4 digits is good, because so is the number I'm going to be working with, but it works with any).
I'll use 2349 (picked at random).
Now, because the number is positive, we'll subtract. We are going to subtract the digits in opposite order. So:
2349-9432 = -7053
Now that the number is negative, we will ADD the digits in opposite order. We'll continue to do this until we notice a pattern. Bear with me.
-7053 + 3507 = -3546
-3546 + 6453 = 2907
2907 - 7092 = -4185 (etc, let me just give you the answers now that you know the process)
1629, -7632, -5265, 360, 279, -495, 99, 0
That's my point. When this process is used, nearly every number imaginable goes to 0. Try it yourself!
EXCEPT 2178 and it's derivatives:
2178, -6534, -2178(!!), 6534, 2178(!!)
Do you see what I mean? Does that make sense?
Can anyone fill me in on why it's unique?
2007-08-07
17:04:10
·
8 answers
·
asked by
Takkuso
3
in
Science & Mathematics
➔ Mathematics
@ Rich Z: My point is that it DOES go to zero for MOST numbers, my question is why isn't that the case for 2178?
2007-08-07
17:19:07 ·
update #1
@Kyle: What doesn't the number 8723 work? According to your theory, it fits a working number doesn't it?
8 = 7+1 Check
2 = 3 - 1 Check
|7 - 2| = |8 - 3| => |5| = |5| Check
But when you go through it it fails immediately:
8723 - 3278 = 5445 -5445 = 0
2007-08-07
18:15:04 ·
update #2
@ McFate: I did my reverse digits differently than you did, I think
When I had a zero at the end of a number, when I did the next thing, I left it off. Example:
6510 - 0156 (I treated the 0 as an irrelevant placeholder and did 6510 - 156).
I believe you wrapped the zero around?
QUOTE:
"v=360, subtracting rv=630
v=-270, adding rv=720"
I'm sure that's the reason we're coming to different conclusions about how many cycle and how many don't. Though I'm not sure the ramifications of that difference.
I'd be VERY interested to see your program though!
2007-08-07
18:22:52 ·
update #3
Also @ McFate: Here's a big difference. You restrained yourself to 4 digits when you started with 4 digits and I didn't. At one of your examples, you got to
QUOTE : "v=999, subtracting rv=9990"
At which point I considered it going to zero:
MY WORK: 999 - 999 = 0
I started at a 4 digit number, but did not require it to stay 4 digits, if my return was only 3 or 2.
2007-08-07
18:25:39 ·
update #4
One more @ McFate: WOW. Just wow. I do have just one more question. If they don't cycle, but don't go to zero, what happens to them?
2007-08-08
02:37:46 ·
update #5
Sorry, I misread what you had said. I understand.
That's really cool. Thank you for that answer.
Now all I need to do is figure out WHY! Haha. I told you 2178 was special. It and 6534 are the only true cyclical numbers. I think your answer plus a combonation of Kyle's answer might be what we're looking for.
2007-08-08
02:40:28 ·
update #6