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Please help!?
A blue car with a mass of mcar = 2000 kg and a yellow truck with mass mtruck = 9000 kg enter an intersection. The truck comes from the south at vtruck = 7 m/s, and the car comes from the west. When the two collide they stick together and slide at an angle of q = 43° north of east.

What is the speed of the pair after the collision?

2007-08-07 17:03:36 · 4 answers · asked by Anonymous in Science & Mathematics Physics

4 answers

This is solved by considering conservation of momentum in the north-south direction as well as the east-west direction.

You know what the north-south momentum is because you have information from the yellow truck.

You can also determine the final momentum in both east-west and north-south directions, because the north-south momentum is conserved, and you have the angle to give you the ratio to the east-west momentum.

Since the two vehicles are stuck after collision, they are treated as a single object with the combined mass and the same velocity.

With this information, you should be able to get the blue car's initial velocity as well as the final velocity.

2007-08-07 20:49:55 · answer #1 · answered by duh 2 · 0 0

This involves the conservation of momentum.
Since v is a vector quality, the velocity of the car must be sufficient to cause the consoldiated masses to slide off at a 43 deg bearing (north of east). This is pretty close to 45 deg, so as an appx, 2000 vcar= 63000 kg-m/s, and vcar is about 31 m/sec. Once you have both velocities, you can compute the velocity of the combined masses, taking care to realize you are dealing with vector quanities.

2007-08-08 01:01:55 · answer #2 · answered by cattbarf 7 · 0 0

Hey, This is impossible to solve without the speed of your first car coming from west (blue car). nice question

2007-08-08 02:02:55 · answer #3 · answered by Anonymous · 0 0

You need to know the velocity of the car to answer the question.

Lorax

2007-08-08 01:00:58 · answer #4 · answered by Lorax 3 · 0 0

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