Normality is a measure of concentration : it is equal to the number of gram equivalents of a solute per kiter of solution.
For an acid N is used to express the concentration of protons in solution.
Since HCl has only 1 proton N = Molarity
In your stock solution you have to find the density of HCl.
It would be 1.18 g/mL
1180 g / L x 38 / 100 = 448.4 g/L
448.4 g/L / 36.46 g/mol = 12.3 M
This is the molar concentration of the stock solution
Diluite to get 0.1 M.
2007-08-07 16:46:45
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answer #1
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answered by Dr.A 7
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12 N Hcl
2016-11-01 23:07:52
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answer #2
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answered by ? 4
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N means normal, in the case of HCl it is the same as molarity.
(i.e. 0.1N HCl = 0.1M HCl). The normality is the concentration of active species. For example for H2SO4, there are two H+ so 0.1M = 0.2N.
38% HCl has 38g of HCl for 62g of water. You can calculate the molarity from that (I believe it is about 16 or 18M), then you have a simple dilution problem to resolve.
2007-08-07 16:47:13
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answer #3
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answered by Christophe G 4
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2016-04-01 02:26:24
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answer #4
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answered by Anonymous
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This Site Might Help You.
RE:
what is the N in "0.1N hcl"?
I need to add .1ml of 0.1N HCL but I don't know what 0.1 N is. I have plenty of stock solution 38% HCL. How do I make .1 n out of 38%?
2015-08-06 02:35:46
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answer #5
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answered by Anonymous
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As mentioned by others, 1 Normal = 1 Molar for HCl.
Concentrated HCl is 38% = 12M = 12N
So you can dilute the conc. acid by 120 to get from 12N to 0.1N
2007-08-07 16:46:11
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answer #6
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answered by reb1240 7
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For the best answers, search on this site https://shorturl.im/avruM
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2016-04-07 07:22:21
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answer #7
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answered by Anonymous
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Its 0.1 Normality. Normals are essentially the same as molarity (for concentration) but they take into account the number of ions that dissociate. HCl is 1:1 so 0.1 normal is 0.1 molarity.
convert the 38% to molarity then determine what type of dilution you need to do of the stock solution to acheive your 0.1 Molar (normal) solution
2007-08-07 16:34:58
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answer #8
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answered by Anonymous
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The "N" stands for normal. It is an expression of normality.
2007-08-07 16:30:46
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answer #9
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answered by bdc3141 4
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H
2014-01-13 22:55:10
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answer #10
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answered by AISHA 1
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