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1. A unifrom electric field with a magnitude of 250 N/C is directed in the positive x direction. A 12 C charge moves from the origin to the point ( 20.0 cm , 50 .0 cm). What is the change in the lectrical potential energy of the system as a result of the change in position of this charge?

2. What is the chage in the electrical potential energy in a lighting bolt of 35 C of charge travel to the ground from a cloud 2.0 Km above the ground in the direction of the field? Assume the electric field is unform and has a magnitude of 1.0 * 10 ^ 6 N/C.

2007-08-07 15:57:55 · 1 answers · asked by confused ~ 1 in Science & Mathematics Physics

1 answers

Let's see

1. Potential energy U=Fd
F- force
d -distance

Electric field intensity E is related to force F=Eq
q - charge in the field
then
U=Eqd
dU=Eq(d2 - d1)

2. Same 'o

dU=Eq(d2 - d1) or since it hits the grround d1=0
we have
dU=Eqd

2007-08-09 03:42:34 · answer #1 · answered by Edward 7 · 0 0

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