Find the inverse function of y=square root of 3x+1/7
That is the square root of 3x+1 and not of the fraction 3x+1/7
2007-08-07 15:44:57 · 4 answers · asked by Nicolás R 1 in Science & Mathematics ➔ Mathematics
To find the inverse function of y= , simply switch x and y.
If I'm understanding you correctly,
the original equation is (sqrt of 3x+1) divided by 7
In that case, we start with switching the variables:
x = sqrt(3y+1) / 7
7x = sqrt(3y+1)
49x^2 = 3y+1
3y+1 = 49x^2
3y = 49x^2 - 1
y = (49x^2 - 1) / 3
That is your inverse equation. Pretty messy but they sometimes are.
2007-08-07 15:57:25 · answer #1 · answered by Anonymous · 1⤊ 0⤋
the inverse function is:
f^(-1)(x)= (49x^2-1)/3
2007-08-07 16:07:34 · answer #2 · answered by GalNextDoor 4 · 0⤊ 0⤋
x = 49y^2/3 - 1/3
2007-08-07 15:56:09 · answer #3 · answered by supastremph 6 · 0⤊ 0⤋
y^2=(3x+1)/49
x=(49y^2-1)/3
2007-08-07 21:50:09 · answer #4 · answered by MathStudent 3 · 0⤊ 0⤋