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area of the sidewalk if it is 1 meter wide?
i think i have the right answer i just want to be sure

2007-08-07 13:46:08 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

two sides of length 13: 13m^2 * 2 = 26 m^2
two sides of length 20: 20m^2 * 2 = 40 m^2
four corners of 1m^2 = 4 m^2
Total is 26 + 40 + 4 = 70 m^2

Another method is to take the outside area of the cement (22 x 15 since it's 1m bigger on each side, in both width and length) and subtract the "hole" in the middle (20 x 13).
22*15 - 20*13 = 330 - 260 = 70 m^2

2007-08-07 13:49:32 · answer #1 · answered by McFate 7 · 0 0

Since it's outside the plot it will have two sides of 13 m and two of 22 m or two of 15 m and two of 20 m. Either way ,since it is 1 m wide, the area is 2* 22 + 2* 13 = 70 m ^2 or
2* 20 + 2 * 15 = 70 m ^2

2007-08-07 20:53:20 · answer #2 · answered by tfloto 6 · 0 0

There are a couple of ways you could go about this. One way is to draw a diagram, and break the cement border up into two 1m x 22m strips, and two 1m x 13m strips. Then just add these up. You could also look at the border as being one rectangle (22m x 15m)minus a smaller rectangle (the plot it surrounds).

2007-08-07 20:52:09 · answer #3 · answered by Anonymous · 0 0

(13+2)(20+2)-13*20=70 m^2

2007-08-07 20:54:12 · answer #4 · answered by Alberd 4 · 0 0

1 meter.

2007-08-07 20:49:22 · answer #5 · answered by Anonymous · 0 2

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