draw the lewis structure of N2O, SO4^2?

Answer 1

The overall structure is N N O. Let * be the electrons for the first N. let x be the electrons for the second N. Let o be the electrons for O.

Put ** to the left of the first N. Put *** and xxx between the first and second N. Put xx between the second N and O. Put oo on the top, bottom, and right side of O. That should give yopu three octets.

Draw S with four O's top and bottom and side to side. Let x be electrons for S. Let * be electrons for O.

Put xx between S and the top O, and xx between S and the bottom O. Put x* between S and the left O, and x* between S and the right O. Put three ** to the top, bottom, and ends of the left and right O's. That will be five octets.

Answer 2

N-O-N O-6 valence N-5 valence 16 total N-O-N F.C's O: 6-4-2 = 0 N's: 5-2-3 = 0 its the most plausible...