Solve the following quadratic equations using the quadratic formula.x^2+6x=0?

Answer 1

Though application of quadratic formula is not required to solve this problem,as requested by you,I am doing the same
x^2+6x+0=0
Comparing it with ax^2+bx+c=0
we get a=1,b=6 and c=0
So, x={-6+-sqrt(36-4*1*0)}/2
=(-6+-6)/2
=0 or -6

Answer 2

You can manage this yourself. The solution to a quadratic equation ax^2+bx+c=0 is (-b+/-(b^2-4ac)^.5)/2a
Here a is1, b is 6 and c is zero. Just plug those values in and see what you get.

Answer 3

X=(-b±√(b^2-4ac))/2a where a=1, b=6, and c=0.
X=(-6±√(6^2-4x1x0))/2x1
X=(-6±√(6^2))/2

X= (-6+6)/2
X=0;
X=(-6-6)/2
X= -6

Answer 4

0, -6

Answer 5

hey I would say the answer is x= -3, x= 1
to tell you the truth I never seen this before and this is my first try so i would like very much if you would email me and tell me if i was wrong or right please......at [e-mail]
if i was wrong could you also tell me the answer?? thanx

Answer 6

a = 1; b = 6; c = 0

x1 = [ -b + sqrt (b^2 - 4ac) ] / 2a
= (- b + b) / 2a
= 0

x2 = [ -b - sqrt (b^2 - 4ac ) ] / 2a
= (- b - b) / 2a
= - 2b / 2a = -6