Algebra Question?

Question

(r+6)^2=10

solve the equation by removing the square roots

thanks

Answer 1

r + 6 = +- sqrt 10
r = -6 +- sqrt 10

Answer 2

Remove the square root by taking the square root of both sides. Then, you have r+6= square root (10). Solve for r by subtracting 6 from both sides. You end up with r=square root (10) - 6 or r=-square root (10) - 6. Hope that helped.

Btw, you could solve this by expanding the r+6 ^2 and using the quadratic formula to figure it out, but that is a rather long process.

Answer 3

We'll use the F.O.I.L method First, Outer, Inner, Last.
(r+6)^2=10
First, we'll multiply the two First terms, the r and r together.
so you get r^2
Second, we'll multiply the two Outer terms, the r and 6 together.
r × 6 = 6r
Third, we'll multiply the two Inner terms, the 6 and r together
6 × r = 6r
Lastly, we'll multiply the two Last terms, the 6 and 6 together
6 × 6 = 36

so we have r^2 + 6r + 6r + 36 = 10
combine like variables
r^2 + 12r + 36 = 10 ....subtract the 10 from both sides
- 10 - 10
------------------------------
r^2 + 12r + 26 = 0 now it is set up as a quadratic equation, and we need to put it into a quadratic formula
which i won't write out, but the answer comes out to either
r= -2.838
r= -9.162

there ya go

Answer 4

There are no square roots to remove.
(r+6)^2=10
r^2+12r+36=10
r^2+12r-26=0
ax^2+bx+c=0 form a=1 b=12 c=-26
x=[-b+-sqrt(b^2-4ac)]/2a
[-12+sqrt(144+104)]/2
=[-12+15.75]/2
and [-12-15.75]/2
=3.75/2=1.875 (solution 1)
and -27.75/2=-13.875 (solution 2)

Answer 5

(r + 6)^2 = 10

take a square root
r + 6 = +/- sqrt(10)

subtract 6 for both sides
r = -6 +/- sqrt(10)

Answer 6

r^2+12r+36=10
r^2+12r+26=0
solve this using the quadratic formula

Answer 7

(r+6)^2=10
Solve.
r+6=+/-√10

r=-6+/-√10

Answer 8

(r+6)^2=10
or (r+6)^2={sq rt10}^2
or r+6=+-sq rt 10
or r=-6+-sq rt(10) ans