Okay my question is mathematical and I want to compare my calculations to someone else's.I'm doing it just for fun although I'm not that good at it.
Here's the situation:
In roulett there is an option of putting on different sections and each section contains 12 numbers. There are 3 sections plus the number zero which is not in any section. All together there are 37 numbers. If I put on 2 out of 3 sections each time I have a 65% chance winning, and since the payout is 3 times I loose one unit of money and win 2 units, alltogether if I hit a number i win one unit. On the other hand if the number is not in my sections I loose 2 units of money. So if I win 13 times out of 20 putting up the same amounts each time, then I end up loosing one unit.
My questions are:
What is the probability of me winning 13 times out of 20?
What is the probability of winning more than 13 times out of 20?
Does it change the probabilities if I keep changing sections or if I use the same 2 sections all the time?
2007-08-07 08:07:18 · 4 answers · asked by amateurgrower 3 in Science & Mathematics ➔ Mathematics
there is no double zero here
2007-08-07 08:08:46 · update #1
man you guys are retarded, if you can't even read the question then why bother answering it?
2007-08-07 10:06:25 · update #2
especially Patrick
2007-08-07 10:08:11 · update #3
especially Patrick
2007-08-07 10:08:12 · update #4
The way to solve any casino probability is to calculate expected value..Here is my equation for a single roll of the roullete wheel
you are betting two units so immediately you are losing two units from your pocket as soon as you drop them on the table...The second part of the equation says that you have a two thirds chance of winning the payoff. From your description I couldn't tell if the payoff is 2 units or 3 units..depending on which
(-2unit) + (..6667*3units) = 0 expected value
(-2unit) + (..6667*2units) = -.67 expected value
either way it adds no value to you...
2007-08-07 10:00:21 · answer #1 · answered by walsh_patr 3 · 0⤊ 1⤋
If I understand you correctly, you have a 65% chance of winning each time you spin the wheel. If that is the case, the probability of winning exactly 13 out of 20 spins is 0.1844. The probability of winning 14 or more times out of 20 spins is 0.6010.
As long as you are betting on two non-zero sections each time, the probability of winning is the same, no matter which two sections you bet on.
2007-08-07 15:20:25 · answer #2 · answered by lithiumdeuteride 7 · 0⤊ 0⤋
The probability is 100% chance that the casino wins in the end.
2007-08-07 15:14:42 · answer #3 · answered by billgoats79 5 · 0⤊ 1⤋
Another point to consider is that most tables have a reuirement of 5 or 10 "units" - so you have to consider that you must bet at least that amount.
2007-08-07 15:16:36 · answer #4 · answered by jgcii 4 · 0⤊ 1⤋