I'm confused about a certain step in a problem at this site:
http://purplemath.com/modules/distform.htm#to_quiz
If you follow the link, it's the very last example. How are they getting y^2? I don't understand.
2007-08-07 07:45:04 · 4 answers · asked by justgoingforadeathdrive 1 in Science & Mathematics ➔ Mathematics
They got the y^2 term when they squared the binomial (-1 - y).
(-1 - y)^2 = (-1 - y)(-1 - y) = (-1)(-1) + (-y)(-1) + (-y)(-1) + (-y)(-y) = 1 + y + y + y^2 = 1 + 2y + y^2
2007-08-07 07:49:27 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
(-1-y)^2=(-1)^2+(-y)^2+(-1)(-y)
=y^2+y+1
2007-08-07 14:53:50 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋
they got it like this...
(-1-y)^2
(-1-y)(-1-y)
foil
(-1)(-1) + (-1)(-y) + (-y)(-1) + (-y)(-y)
1+y+y+y^2
y^2 + 2y +1
2007-08-07 14:56:37 · answer #3 · answered by answersguy1691 2 · 0⤊ 0⤋
Distance formula:
_________
d = /(x^2)+(y^2)
2007-08-07 14:51:09 · answer #4 · answered by Mitchell 5 · 0⤊ 0⤋