2007-08-07 05:45:55 · 6 answers · asked by booboobear_619 1 in Science & Mathematics ➔ Mathematics
x = [ 3 ± √(9 + 28) ] / 2
x = [ 3 ± √37 ] / 2
x = 9.08 / 2 , x = - 3.08 / 2
x = 4.52 , x = - 1.54
2007-08-07 06:36:17 · answer #1 · answered by Como 7 · 2⤊ 0⤋
It does not factor into integral factors so by the quadratic formula x= 3 + sq rt (3^2-4(1)(-7))/2 = (3+sq rt 37)/2 and the other component which is then (3-sq rt 37)/2
2007-08-07 12:53:59 · answer #2 · answered by chasrmck 6 · 0⤊ 0⤋
Use the quadratic equation:
x= -b +/- the square root of b^2 - 4ac
-----------------------------------------------------
2a
plug in the numbers A= 1 B= -3 C= -7
Final answer: x= 3/2 - square root of 37/2
and x= 3/2 + square root of 37/2
2007-08-07 12:53:54 · answer #3 · answered by N :O) 3 · 0⤊ 0⤋
x^2 - 3x - 7 = 0
since the equation can not be factor, use quadratic formula
quardratic formula:
-b +/- sqrt(b^2 - 4ac)
-------------------------
............ 2a
standard form:
ax^2 + bx + c = 0
a = 1
b = -3
c = -7
-(-3) +/- sqrt[ (-3)^2 - 4(1)(-7) ]
---------------------------------------
................ 2(1)
3 +/- sqrt(9 + 28)
----------------------
........ 2
3 +/- sqrt(37)
----------------
....... 2
so x = [ 3 + sqrt(37) / 2, or [ 3 - sqrt(37) ] / 2
2007-08-07 12:54:34 · answer #4 · answered by 7 · 0⤊ 0⤋
multiplies to -7 adds to -3
since nothing comes to mind. use quadratic equation
2007-08-07 12:49:33 · answer #5 · answered by (+_+) B 4 · 0⤊ 0⤋
i tried. I couldn't figure it out.
2007-08-07 12:54:55 · answer #6 · answered by Lani B 2 · 0⤊ 1⤋