Hypothesis testing?

Question

A plant breeder claims that a new variety of fruit bush he has produced gives a higher yield of fruit than the variety it will replace. A random sample of 10 bushes of the new variety is grown and the yields of the bushes recorded. The old variety has an average yeild of 5.2kg/bush. It is assummed that the yield from each bush is an independent observation from a normal distribution. Test at 5% level of significance, the breeder's claim.

What do you think the null and altenative hypothesis are? Please explain!

Side question: How big is the range of the p-value(observed significance value)?

Answer 1

It seems you have not understood the previous explanation I gave.
Ho is that the new variety does not yield more fruit. That is, mean = 5.2 kg/bush
We know that the alternative is Ha; mean is greater that 5.2, because we are testing to see if the new variety yields a HIGHER amount of fruit.
words like increase, more, higher indicate you must do a one tailed test and the critical region will be on the upper tail.
Words like decrease, less, reduction are key words to tell you you have to do a lower tail test.

Answer 2

Ho: µ = 5.2kg/bu
Ha: µ > 5.2kg/bu (one-tailed t-test)
α = 0.05
tCritical = 1.833 (9 degrees of freedom)

I can't go any further because an estimate of the population standard deviation and mean are required.

Answer 3

You need to also mention what the mean and standard deviation of the sample is.

From that we can calculate
test stat = (xbar - 5.2) / (s/sqrt(10))
and then find the p value from this.

Answer 4

You must give the standard deviation