Have to simplify this mathproblem and I'm getting nowwhere!!
13x^3 - (-2x^2 + 3x)(-2x+3x^2)
I know it's should be simple but I'm still stuck!
2007-08-07 04:54:01 · 3 answers · asked by Bluewolf 1 in Science & Mathematics ➔ Mathematics
13x³ - (-2x² + 3x)(-2x+3x²)
First factor the x from each term.
13x³ - x(-2x + 3) x(-2+3x)
13x³ - x²(-2x + 3)(-2+3x)
Note that (-2x + 3)(-2+3x) = 4x - 6x² + 9x - 6 = -(6x² - 13x + 6)
13x³ + x²(6x² - 13x + 6)
Factor out the x²
x²(13x) + x²(6x² - 13x + 6)
x²(13x + 6x² - 13x + 6)
x²(6x² + 6)
Now factor out the 6
6x²(x² + 1)
2007-08-07 05:04:06 · answer #1 · answered by Astral Walker 7 · 0⤊ 0⤋
13x^3 - (-2x^2 + 3x)(-2x+3x^2)
=13x^3-(4x^3-6x^4-6x^2+9x^3)
=13x^3-4x^3+6x^4+6x^2-9x^3
=13x^3-4x^3-9x^3+6x^4+6x^2
=6x^4+6x^2
2007-08-07 04:58:55 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋
expand the brackets
2007-08-07 05:04:43 · answer #3 · answered by herbman76 2 · 0⤊ 0⤋