A car travels a certain distance taking 7 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 5 hrs. What is the distance travelled?
2007-08-07 04:09:09 · 4 answers · asked by Lolla 2 in Science & Mathematics ➔ Physics
plz answer with explanation.
2007-08-07 04:09:57 · update #1
Let d be the distance travelled.
d = v.t where v is the speed and t the time.
In onward direction, d = 7v
In return direction, d = 5(v + 12) = 7v
So, 7v = 5v + 60
2v = 60
v = 30
So, distance d = 210 kms
2007-08-07 04:45:14 · answer #1 · answered by Swamy 7 · 0⤊ 0⤋
The speed during onward journey = S/ 7.
The speed during return journey = S/5
It is given that [S/ 5 - S/7 ] = 12 km/h.
S {2 /35} = 12
S = 210 km.
Total distance traveled 420 km
2007-08-07 05:59:50 · answer #2 · answered by Pearlsawme 7 · 0⤊ 0⤋
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2016-10-14 07:14:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
distance = velocity*time
You know that the distance is the same going each way.
So you can also say that:
d = v1*t1
and
d = v2*t2.
and, to wrap it up:
v1*t1 = v2*t2
We'll call v1 = x, and v2 = x+12.
You can go from there, I'm sure.
2007-08-07 04:13:35 · answer #4 · answered by Brian L 7 · 0⤊ 0⤋