find out the length of the median AD of triangle whose vertices are A(-2,6), B(5,-3),C(-7,7).please help me.?

Question

i am desperately waiting here for the answer. will be very grateful if you work out the problem and say me the answer with steps. it is based on coordinate geometry. i am having all the hopes on yahoo answers community. please post ur reply if u know to solve it.

Answer 1

D is the mid point of BC
D(- 1 , 2)
A(- 2 , 6)
AD² = (6 - 2)² + (- 2 + 1)²
AD² = 4² + (-1)²
AD² = 17
AD = √17

Answer 2

Given 3 medians, you may build a triangle, although that's no longer unique. -------- thoughts to construct the triangle: start up at 2/3 of the three segments of the medians, turn them around till you detect a triangle.

Answer 3

for your easiness i divide the answer in to following steps

here u have to find length of median AD
Step 1 ;
first find mid point of BC as shown
(X,Y)=(5-7/2, -3+7/2)
(x,y)=(-1,2)

Step 2;
now the point u find in step 1 is D
just find the length now
A(-2,6) :D(-1,2)

AD=[{-1-(-2)}^2+(2-6)^2}]^1/2

AD=[(-1+2)^2+(-4)^2]^1/2

AD=[1 +16]^1/2
AD=17^1/2

Answer 4

Midpoint of BC (D) = (5-7)/2,(-3+7)/2 = -1,2

Length = sqrt(17)

Answer 5

Midpoint of BC is (5+(-7-5)/2),-3+(7--3)/2) =(-1,2)

AD = sqr((2-6)^2+(-1--2)^2) = sqr(16+1) = sqr17.

Answer 6

point D is (-1..2) mid point of BC;
length of median AD=sqrt(1+16=sqrt(17)).ANS

Answer 7

well....
D is mid point of BC
therfore..D IS(-1,2)
A is (-2,6)
i.e .., length of median AD =17^0.5=(square root of 17)
bye.
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