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I understand the majority of it e.g.
I used a total of 629 kWh over 77 days.
The statement says that the first 190 of these were charged at 16.383 pence (£31.13) and the next 439 were charged at 8.491 pence (£37.28) for a total of £68.41p

What confuses me is this additional information on the statement:
'How we calculate your electricity charges: 16.383 pence per kWh for the first 2.466 kWhs used a day, and 8.491 pence per kWh for the rest.'
To me this implies that the first few kWhs of electricity used each day are charged at the higher rate and those that are used after this are charged at the lower price (for the rest of the day). Now I've been told that this relates to night useage (cheaper) and day useage (more costly) but how does my 'service provider' separate my useage into kWhs used up to 2.466 kWhs? Am I thinking about this in the wrong way?

2007-08-07 01:03:41 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

They don't separate the first 2.466 KWhrs into night and day. If you use the first 2.466 KWhrs at night, you will still be charged the higher rate. Unless they put in a timer of some sort or monitor your line in some way, they have no idea when you are using the electricity.
Where I am, I believe that I can agree to use items like the washer and the dryer at night and get a cheaper rate, but they come and put some kind of monitor on, and I would pay more to use them during the day.

2007-08-14 10:31:45 · answer #1 · answered by hemidemisemiquaver 2 · 0 0

I can only assume that they do it by averaging.
It's the only logical method since the meter is not read on a daily basis.

2007-08-07 01:23:21 · answer #2 · answered by ed 7 · 0 0

comprise cstring #comprise iomanip #comprise iostream using namespace std; const int 62e5cef85d46f1a5a2144d9fd463b79e62e5cef85d46f1a5a2144d9fd463b79e62e5cef85d46f1a5a2144d9fd463b79e62e5cef85d46f1a5a2144d9fd463b79e = one thousand; int important() { // variables char n[62e5cef85d46f1a5a2144d9fd463b79e62e5cef85d46f1a5a2144d9fd463b79e62e5cef85d46f1a5a2144d9fd463b79e62e5cef85d46f1a5a2144d9fd463b79e]; // username double rs; // rates int t; // variety of instruments // instant consumer if (t <= a hundred) { rs = t*0.60; } else if (t <= two hundred) { rs = t*0.80; } else { rs = t*0.ninety; } if (rs < 50) { rs = 50; } if (t > 3 hundred) { int addCharge = rs*0.15; rs = rs+addCharge; } // output return 0; }

2016-12-11 12:47:00 · answer #3 · answered by turnbow 4 · 0 0

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