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4^(n/2) x c^(n - 1) x 6^(1 - n)

2007-08-06 23:22:35 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

(2^n)(c^n)(6) / c (6^n)

2007-08-06 23:29:19 · answer #1 · answered by Como 7 · 1 0

The solution is 12c^(n-1)

Here is how:

4^(n/2) = sqrt 4 ^n
= 2^n
2^n * c^(n-1) * 6^(1-n)
= 12^(n + 1 - n) * c^(n-1)
= 12 * c^(n-1)

12 * c^(n-1)

2007-08-08 20:54:04 · answer #2 · answered by Anonymous · 0 1

Simplify ability to eliminate parentheses () and positioned like words jointly. for the reason that there are not any parenthesis given, we in basic terms combine like words. 2a and 6a are like words for the reason that they have an identical literal coefficient, "a". 3b and -7b are additionally like words, with an identical literal coefficient, "b". Combining the two instruments of like words ends up in: 2a+6a = 8a 3b-7b = -4b for this reason, the simplified variety is: 8a-4b Going further by detect a typical ingredient of the two words such that that's going to become 4(2a-b) isn't any longer "simplifying" yet "factoring".

2016-12-11 12:44:14 · answer #3 · answered by wingert 4 · 0 0

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