Girls = 7
Girls Nipples = 14
Bags = 49
Cats per Bag = 56
Cats = 56 x 49 = 2744
Cat Nipples = 2744 x 7 = 19208
Total = 19208 + 14 = 19222
2007-08-06 21:14:00
·
answer #1
·
answered by Anonymous
·
0⤊
2⤋
Each bag has 7 big cats and each of these has 7 small cats.
So there are 7*7 small cats + 7 big cats or 56 cats per bag
(7 girls) * (7 bags) * (56 cats) * (7 nipples per cat) = 19,208
If you are counting nipples on the girls you must add an additional 14 so:
Cat nipples = 19,208
Girl nipples = 14
Total all nipples = 19,222
2007-08-06 21:21:41
·
answer #2
·
answered by Captain Mephisto 7
·
1⤊
1⤋
number of girls = 7
number of bags = 49
number of cats in each bag=56
total number of cats = 56*49 = 2744
Now each cat has 7 nipples so total number of nipples from cats=2744*7 = 19208
7 girls have 14 nipples
total number of nipples in the bus = 19208+14 = 19222
2007-08-06 21:42:11
·
answer #3
·
answered by tester 1
·
0⤊
0⤋
We can calculate the nipples for the 3 different beings:
7 girls = 14 nipples
7 * 7 * 7 big cats = 343 big cats so = 343 * 7 = 2401 nipples
7 * 7 * 7 * 7 small cats = 2401 small cats so 2401 * 7 = 16807 nipples
I f we sum all = 14 + 2401 + 16807 = 19222 nipples !
2007-08-06 21:36:19
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
7 girls = 14 nipples
7 girls x 7 bags x 7 big cats x 7nipples/cat = 2,401
plus
49 big cats x 7 small cats x 7 nipples /small cat = 2,401
therefore: 14 + 2,401 + 2,401 = 4,816 nipples
2007-08-06 21:44:27
·
answer #5
·
answered by ferdie 2
·
0⤊
0⤋
7 nipples x 7 small cats +
7 nipples x 7 cats x 7
--------------------------------------
392 nipples in 1 bag
each girl has 7 bags => 2744 nipples.
they are 7 girls => 19208 nipples.
but the girls has nipples => 19208 + (2x 7)= 19222.
Answer : 19222 nipples. :D
2007-08-06 21:17:26
·
answer #6
·
answered by iulydj 2
·
0⤊
1⤋
how many nipples does each girl have? How many boys are in the bus? what about the bus driver? don't the boys and the driver have nipples as well? How many do they have?
2007-08-06 21:23:00
·
answer #7
·
answered by trogwolf 3
·
0⤊
1⤋