Pls answer these:?

Question

Find the linear function whose graph is perpendicular to the graph of given equation and passes through the given point.Use the slope-intercept form.
1. 5x+2y=10; (3,-5)
2. 3x+y=5; (2,-4)
3. 5x-3y=7; (8,-2)
4. 3x+8y=4; (0,4)
5. 3x-y=4; (2,7)
6. 2x-y=5; (-1,4)
7. -3x|+y=7; (-3,1)
8. 3x-y=2; (6,-1)

Answer 1

hahah.....a this is your assignment right?

to find the perpendicular line remember this = -1/m


1. the slope is m = -5/2 so -1/-5/2 = 2/5
5y - 2x = then substitute x and y by the given point
so 5y-2x = 5(-5) -2(3)
ans: 5y -2x = -31

2. 3x+y=5; (2,-4)
3y - x = 3(-4) -(2)
ans: 3y -x= -14

3. 5x-3y=7; (8,-2)
5y + 3x = 5(-2) + 3(8)
ans: 5y + 3x = 14

4. 3x+8y=4; (0,4)
3y - 8x = 3(4) - 8(0)
ans: 3y - 8x = 12
5. 3x-y=4; (2,7)
3y + x = 3(7) + (2)
ans: 3y + x = 23

6. 2x-y=5; (-1,4)
2y + x = 2(4) + (-1)
ans: 2y + x = 7

7. -3x+y=7; (-3,1)
3y + x= 3(1) + -3
ans: 3y + x = 0

8. 3x-y=2; (6,-1)
3y + x = 3(-1) + 6
ans; 3y + x = 3

please choose me

Answer 2

y = mx + b ...... the standard form with m = slope and -1/m is the slope of a line perpendicular to this one

1. y = (-5/2)x + 10 so -1/m = 2/5
Perpendicular line: y = (2/5)x + c and -5 = 6/5 + c so c = -31/5
y = (2/5)x - 31/5

2. y = -3x + 5 so -1/m = 1/3
Perpendicular line: y = (1/3)x + c and c = -4 - 2/3 = -14/3
y = (1/3)x -14/3

3. y = (5/3)x - 7 so -1/m = -3/5
Perpendicular line: y = (-3/5)x + c and c = 14/5
y = (-3/5)x + 14/5

4. y = (-3/8)x + 1/2 so -1/m = 8/3
Perpendicular line: y = (8/3)x + c and c = 4
y = (8/3)x + 4

5. y = 3x - 4 so -1/m = -1/3
Perpendicular line: y = (-1/3)x + c and c = 7 + 2/3 = 23/3
y = (-1/3)x + 23/3

6. y = 2x -5 so -1/m = -1/2
Perpendicular line: y = (-1/2)x + c and c = 4 - 3/2 = 5/2
y = (-1/2)x - 5/2

7. There appears to be a line after the -3x and I don't know what that means so I will ignore it
y = 3x + 7 so -1/m = -1/3
Perpendicular line: y = (-1/3)x + c and c = 1 -1 =0
y = (-1/3)x

8. y = 3x - 2 and -1/m = -1/3
Perpendicular line: y = (-1/3)x + c and c=-1 + 2 = 1
y = (-1/3)x + 1

Answer 3

1. 5x + 2y = 10
2y = -5x +10
y = -5/2x + 5
therefore the slope is -5/2
m1*m2 = -1
-5/2*m2 = -1
m2 = 2/5

therefore the linear function is
y - y1 = m(x - x1)
y + 5 = 2/5(x - 3)
5(y + 5) = 2(x - 3)
5y + 25 = 2x - 6
5y = 2x -6 - 25
5y = 2x - 31

2. 3x + y = 5
y = -3x + 5
therefore the slope is -3.
m1*m2 = -1
-3*m2 = -1
m2 = 1/3

therefore the linear function is
y - y1 = m(x - x1)
y + 4 = 1/3(x - 2)
3(y + 4) = x - 2
3y +12 = x - 2
3y = x - 2 -12
3y = x -14

3. 5x-3y=7
3y = 5x - 7
y = 5/3x - 7/3
therefore the slope os 5/3
m1*m2 = -1
5/3*m2 = -1
m2 = -3/5
therefore the linear function is
y - y1 = m(x - x1)
y + 2 = -3/5(x - 8)
5(y + 2) = -3(x - 8)
5y + 10 = -3x + 24
5y = -3x + 24 - 10
5y = 3x + 14

4. 3x+8y=4
8y = -3x +4
y = -3/8x + 1/2
therefore the slope is -3/8
m1*m2=-1
-3/8*m2=-1
m2 = 8/3

therefore the linear function is
y - y1 = m(x - x1)
y - 4 =8/3(x - 0)
3(y - 4) = 8x
3y - 12 = 8x
3y = 8x + 12

5. 3x - y = 4
y = 3x + 4
therefore the slope is 3
m1*m2 = -1
3*m2 = -1
m2 = -1/3

therefore the linear function is
y - y1 = m(x -x1)
y - 7 = -1/3(x - 2)
3(y - 7) = -x + 2
3y - 21 = -x + 2
3y = -x +2 +21
3y = -x + 23

6. 2x - y = 5
y = 2x - 5
therefore the slope is 2.
m1*m2 = -1
2*m2 = -1
m2 = -1/2

therefore the linear function is
y -y1 = m(x - x1)
y - 4 = -1/2(x +1)
2(y - 4) = -x - 1
2y - 8 = -x -1
2y = -x -1 + 8
2y = -x + 7

7. -3x + y = 7
y = 3x + 7
therefore the slope is 3

m1*m2 = -1
3*m2 = -1
m2 = -1/3

therefore the linear function is
y - y1 = m(x - x1)
y - 1 = -1/3(x + 3)
3(y - 1) = -x -3
3y - 1 = -x -3
3y = -x - 3 + 1
3y = -x - 2

8. 3x - y = 2
y = 3x - 2
therefore the slope is 3

m1*m2 = -1
3*m2 = -1
m2 = -1/3

therefore the linear function is
y - y1 = m(x - x1)
y + 1 = -1/3(x - 6)
3(y + 1) = -x + 6
3y + 3 = -x + 6
3y = -x + 6 - 3
3y = -x +3