What is the second derivative of this?

1 ⤊

e^kx

2007-08-06 16:58:22 · 3 answers · asked by westbound65 1 in Science & Mathematics ➔ Mathematics

f (x) = e^(kx)
f `(x) = k e^(kx)
f "(x) = k² e^(kx)

2007-08-06 20:49:21 · answer #1 · answered by Como 7 · 1⤊ 0⤋

y = e^(kx)
y' = dy/dx = ke^(kx)
y" = (k^2)e^(kx)

2007-08-06 17:05:59 · answer #2 · answered by gudspeling 7 · 0⤊ 0⤋

f''(x) = k^2 * e^(k*x) (or "k^2e^(kx)" if one prefers)

2007-08-06 17:07:30 · answer #3 · answered by bimeateater 7 · 0⤊ 0⤋