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1) find the magnitude of the magnetic force on a proton moving with velocity 4.46 Mm/s in the positive x direction in a magnetic field of 1.85 T in the positive z direction. Answer in units of pN.

I got 9.33495 x10^-34, but im not sure if I am correct.

2007-08-06 15:25:03 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

F = q*v*B since speed is perpendicular to field direction

F = 1.6*10^-19 Coul*4.46*10^6 m/s*1.85 T

= 1.32 x 10^-12 Nt = 1.32 pN

2007-08-06 15:29:50 · answer #1 · answered by nyphdinmd 7 · 0 0

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