2) A long straight wire carries a current of 13.9 A. An electron travels at 24400 m/s parallel to the wire, 52.2 cm from the wire. The permeability of free space is 1.25664 x 10^-6 N/A2 and the charge on an electron is 1.6 x10^-19 C. What force does the magnetic field of the current exert on the moving electron? Answer in units of N...
2007-08-06 14:54:08 · 2 answers · asked by jay b 1 in Science & Mathematics ➔ Physics
Mgentic field of the wire at a distance d is
B = u0*I/(2*pi*d)
This field is perpendicular to the wire and to direction the electron travels in. So force:
F = qvB = -e v u0 I/(2*pi*d)
F = -1.6x10^-19 Coul *24400 m/s *1.25664x10^-6 N/A^2 *13.9A/(2*pi*0.522m)
Note that Coul/sec = A. I leave teh arithmetic to you.
2007-08-06 15:03:13 · answer #1 · answered by nyphdinmd 7 · 1⤊ 0⤋
physics is the right spelling.Not physic
2007-08-06 14:57:59 · answer #2 · answered by Anonymous · 0⤊ 1⤋