Really Hard Algebra Question. Stuck.?

Question

Given the function rules and domains, find the associated ranges.

(a) f (x) = 2x + 3, domain = {0, 1, 2}

(b) f (x) = 0, domain = {0, 1, 2}

Answer 1

Just take the three values and plug them in for x.
a) f(0) = 2(0) + 3 = 3
f(1) = 2(1) + 3 = 5
f(2) = 2(2) + 3 = 7
Range = {3, 5, 7}

b) f(x) = 0. There are no x's in f(x), so
f(0) = 0, f(1) = 0, f(2) = 0.
It doesn't depend on the x value.
Range = {0}

Answer 2

a. f(0) = 2(0) + 3
= 0 + 3
= 3
f(1) = 2(1) + 3
= 2 + 3
= 5
f(2) = 2(2) + 3
= 4 + 3
= 7
Range= {3,5,7}
b. f(0) = 0
f(1) = 0
f(2) = 0
Range = {0}

Answer 3

b. f(x) has a range of 0, since it is zero for all values of x in the domain
a. Substitute x=0,1 and 2 in the function. The range is the lowest to highest of the values of f(x).