First, subtract Ax from both sides, to leave the B term on its own:
Ax + By = C
Ax + By - Ax = C - Ax
Ax - Ax + By = C - Ax
0 + By = C - Ax
By = C - Ax
Now divide both sides by y to leave B by itself:
By = C - Ax
By/y = (C - Ax)/y
B = (C - Ax)/y
2007-08-06 13:53:39
·
answer #1
·
answered by McFate 7
·
1⤊
0⤋
Thats the standard form for linear equations. I think that the answer is B = AX - C. Not really sure.
2007-08-06 21:13:45
·
answer #2
·
answered by Steph 2
·
0⤊
1⤋
Ax + By= C
By = C - Ax
B = (C-Ax) / y
2007-08-06 20:54:01
·
answer #3
·
answered by Reese 4
·
0⤊
0⤋
Ax+By=C
or,By=C-Ax
or,B=(C-Ax)/y [dividing both sides by y]
2007-08-06 20:57:34
·
answer #4
·
answered by alpha 7
·
3⤊
0⤋
b= c-ax/y
2007-08-06 20:53:43
·
answer #5
·
answered by blah 3
·
0⤊
0⤋
where is the given??
2007-08-06 20:55:56
·
answer #6
·
answered by micah_joyce01 2
·
0⤊
1⤋