Here's the question. I'm having trouble with it.
Divide.
2x^2y-6xy^2+12xy / 2xy
Can you help me? Thanks, if you can.
:-D
2007-08-06 13:48:21 · 7 answers · asked by Nerds Rule! 6 in Science & Mathematics ➔ Mathematics
I assume the entire thing is divided:
(2x^2y - 6xy^2 + 12xy) / 2xy
All three of the terms in the numerator divides by 2xy evenly:
2x^2y / 2xy = x(2xy)/2xy = x
-6xy^2 / 2xy = -3y(2xy)/2xy = -3y
12xy / 2xy = 6(2xy)/2xy = 6
So the answer is
x - 3y + 6
2007-08-06 13:50:53 · answer #1 · answered by McFate 7 · 2⤊ 0⤋
2x^2y-6xy^2+12xy/2xy = x-3y+6 ANS
2007-08-06 20:55:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋
2x^2y-6xy^2+12xy / 2xy
All three of the terms in the numerator divides by 2xy evenly:
2x^2y/2xy = x
2007-08-06 20:51:31 · answer #3 · answered by Anonymous · 0⤊ 1⤋
2x²y-6xy²+12xy / 2xy
= 2x²y/(2xy) - 6xy²/(2xy) + 12xy/(2xy)
= x - 3y + 6
2007-08-06 20:51:31 · answer #4 · answered by Reese 4 · 0⤊ 0⤋
(2X²Y - 6XY² +12XY) / (2XY)
separate into 3 fractions
2X²Y/(2XY) - 6XY²/(2XY) + 12XY/(2XY)
gives, term by term
X - 3Y + 6
2007-08-06 20:56:15 · answer #5 · answered by Anonymous · 0⤊ 0⤋
2x^2 y-6x y^2+12xy/2xy
=(2x^2 y/2xy)-(6x y^2/2xy)+(12xy/2xy)
=x-3y+6 ans
2007-08-06 20:54:25 · answer #6 · answered by alpha 7 · 1⤊ 0⤋
Factor 2xy from the numerator.
2xy(x-3y+6) / 2xy
2xy cancel out
x - 3y + 6
2007-08-06 20:51:51 · answer #7 · answered by UnknownD 6 · 0⤊ 0⤋