what's the diff b/w fraction 2/3 and repeating decimal 0.39393939 in terms of a fraction?
2007-08-06 12:09:15 · 5 answers · asked by Olivia R 1 in Science & Mathematics ➔ Mathematics
Convert 0.393939.... into a fraction.
100x = 39.39393...
x = 0.393939...
99x = 39.393939...-0.393939... = 39
x = 39/99
Now subtract the two fractions.
2007-08-06 12:13:19 · answer #1 · answered by Mathsorcerer 7 · 1⤊ 0⤋
First turn 0.393939393939... into a fraction.
0.393939393....*100 = 39.393939393....
39.3939393939- .393939393 = 39 = (100 - 1).39393939...
So 99*.39393939... = 39. Divide through by 99.
.3939393..... = 39/99.
Now we need multiply 2/3*(33)/(33) = 66/99. So the difference is (66 - 39)/99 = 27/99 = 3/11.
2007-08-06 12:16:50 · answer #2 · answered by Edgar Greenberg 5 · 0⤊ 0⤋
the repeating decimal 0.3939.... is 39/99 = 13/33, and 2/3 = 22/33, so the difference is (22-13)/33 = 9/33 = 3/11.
2007-08-06 12:14:14 · answer #3 · answered by Philo 7 · 1⤊ 0⤋
Using a geometric progression, you can find that .39... is equivalent to 39/99.
2/3 is 66/99
Hence the difference is 27/99 or 3/11
2007-08-06 12:17:50 · answer #4 · answered by supastremph 6 · 0⤊ 0⤋
3/11
2007-08-06 12:14:23 · answer #5 · answered by jeffnbex 2 · 0⤊ 0⤋