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-6 + x^2 - 5x
so how would u arrange it so it would be like
ax^2 + bx+ c??? and not

-c + ax^2 - b
thanks

2007-08-06 10:17:50 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

rearrange terms in quad function order
x^2-5x-6


if the "a" value...in this case 1...is positive, parabola opens upward
if the a value is negative, the curve opens downward..

2007-08-06 10:23:45 · answer #1 · answered by plb5000 3 · 0 1

You don't really have to rearrange it, you can just look at the coefficient of x^2. Positive "a," it points up (i.e., has a minimum and increases in both directions away from the minimum). You don't really have to do anything else.

Though I'm assuming that you have a "y =" that is implied but omitted:

y = -6 + x^2 - 5x

In this case the coefficient of x^2 is positive 1, so this parabola points up (looks like 'U').

You could reorder the terms (remember, addition is commutative), but it doesn't change much:

y = x^2 - 5x - 6

... traditionally the terms are ordered by decreasing degree of x.

2007-08-06 10:21:17 · answer #2 · answered by McFate 7 · 1 0

+ x^2 is U shaped
- x^2 is n shaped

-6 + x^2 - 5x =>+ x^2
1x^2 -5x-6 = ax^2 + bx+ c

2007-08-06 10:21:24 · answer #3 · answered by harry m 6 · 1 0

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