English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A pair of narrow slits, separated by 1.8 mm is illuminated by a monochromatic light source. Light waves arrive at the two slits in phase. A fringe pattern is observed on a screen 4.8 m from the slits
monochromatic light of 450 nm wavelength is used. The angular separation between adjacent dark fringes on the screen, measured at the slits, in m rad, is closest to:


a.0.20
b. 0.36
c. 0.15
d. 0.30
e. 0.25

2007-08-06 09:16:17 · 2 answers · asked by ABC 4 in Science & Mathematics Physics

I think it is about 0.125 mrad, but I am not sure (if I take m=0)

2007-08-06 09:24:53 · update #1

2 answers

Spacing of the fringes is given by:

dy = s/a*wl where s =distance to screen, a = slit separation, and wl = wavelength

angular separation dq = dy/s = wl/a = 450 nm/1.8 mm = 0.25 mrad

2007-08-06 09:26:05 · answer #1 · answered by nyphdinmd 7 · 1 0

It's a trick question....the answer is actually "bleen"

2007-08-06 16:24:33 · answer #2 · answered by Cheese 4 · 0 1

fedest.com, questions and answers